To be precise, this is what happens in the double digit scan for together on the empty cells of the left middle major square. We are not certain at this point which of the two digits will finally occupy which of the two cells, but taking the two cells together, we are certain that digits will certainly occupy these two cells and in no other empty cell in parent zones R6 and left middle square. That means, these two digits light up or affect the intersecting cell R6C1 and reduce its possible digit subset to single digit 3.Īs a byproduct the leftover two digits form a Cycle of (1,8) in R6C2 and R6C3. īoth digits 1 and 8 appear together in column C1 but not in any cell of the left major square. The possible digit subset in the three empty cells is. With six digits filled in the left middle major square, it is a very promising zone to look for more valid cell hits. Explanation on how Cycle (1,8) is formed and how it results in a breakthrough Never lose an opportunity for a valid cell hit by row column scan. Next valid cell is R4C6 7 by scan for 7 in R5, R6, C7. This leaves the single cell R2C1 for 3 and the byproduct Cycle of (5,6,7) in the other three empty cells of C1. Still analyzing this promising neighborhood we detect the possibility of the next breakthrough of R2C1 3 by parallel scan for 3 on empty cells of C1.ģ in bottom left major square eliminates R7C1 for 3 and 3 in R1 and R3, eliminate the other two empty cells R1C1 and R3C1 for 3. Advanced Sudoku technique of parallel digit scan for 3 Primarily, with only two cells left for the two digits, a breakthrough Cycle of (1,8) is formed in a single strike and it leaves only the cell R6C1 for digit 4 by exception in left middle major square.
This eliminates the cell R6C1 for any of the two digits. Instead of scanning the promising empty cells of a major square FOR A SINGLE DIGIT, in a double digit scan, the promising empty cells of a major square are scanned for TWO DIGITS TOGETHER.Īs appear together in C1, and also as none of these two digits are placed yet in left middle major square, we get Cycle (1,8) in cells R6C2, R6C3 by a double digit scan of in C1. This creates an opportunity for us to apply advanced technique of double digit scan to get a valid cell hit. Advanced Sudoku technique of double digit scan It is followed immediately by a second valid cell for 7 in the promising neighborhood of left middle major square: R5C2 7 by scan for 7 in R6. Step by step solution to the New York Times Sudoku Hard 17th February, 2021: Stage 1: Breakthroughs by Double digit scan, Parallel digit scan and and Cyclesįirst valid cell by row column scan is for 5: R4C2 5 by scan for 5 in R5, R6.
The New York Times Sudoku Hard, 17th February, 2021īefore going through the solution solve the puzzle first.
New York Times Sudoku Hard 17 February, 2021 solved in four stages that explain all breakthroughs and how those are achieved by advanced Sudoku techniques. New York Times Sudoku hard puzzle 17th February, 2021 Solved in easy steps
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